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NEW QUESTION: 1
Your network contains a System Center 2012 R2 Configuration Manager Service Pack 1 (SP1) environment.
You need to create a report that lists all of the client computers that do not have an Application named App1 installed.
Which query should you use to create the report?
A. SELECT SYS.Netbios_Name0, ARP.DisplayName0FROM v_R_System AS SYS INNER JOINV_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID - ARP.ResourceID WHERE ARP.DisplayName0NOT LIKE 'App1'
B. SELECT SYS.Netbios_Name0 from v_R_System SYSWHERE SYS.ResourceID IN(SELECT SYS.ResourceIDFROM v_R_System ASSYS INNER JOINv_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID - ARP.ResourceID. WHERE ARP.DisplayName0 = 'App1')
C. SELECT SYS.Netbios_Name0 from v_R_System SYSWHERE SYS.ResourceID NOT IN(SELECT SYS.ResourceIDFROM v_R_SystemAS SYS INNER JOINv_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID = ARP.ResourceID WHERE ARP.DisplayName0 = 'App1')
D. SELECTSYS.Netbios_Name0, ARP.DisplayName0FROM v_R_System AS SYS INNER JOINv_GS_ADD_REMOVE_PROGRAMS AS ARP ON SYS.ResourceID = ARP. ResourceID WHERE ARP.DisplayName0 NOT IN ('App1')
Answer: C
Explanation:
Explanation/Reference:
Explanation:
SELECT computer name FROM table v_R_System (SQL Syntax)
WHERE resource ResourceID is NOT IN
Add Remove Programs WHERE DisplayName0 = 'App1'
SQL INNER JOIN Keyword
The INNER JOINkeyword returns rows when there is atleast one match in both tables.

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